floor framing

Solution to Problem 543 | Floor Framing

Problem 543
A portion of the floor plan of a building is shown in Fig. P-543. The total loading (including live and dead loads) in each bay is as shown. Select the lightest suitable W-shape if the allowable flexural stress is 120 MPa.
 

For Girders (G - 2) | Solution to Problem 542

For Girders (G - 2)

542-girder-g2.jpg$S_{required} = \dfrac{M}{f_b} = \dfrac{120(1000^2)}{120}$
$S_{required} = 1000 \times 10^3 \, \text{mm}^3$
 

From Appendix B, Table B-2 Properties of Wide-Flange Sections (W Shapes): SI Units, of text book:

For Beams (B - 3) | Solution to Problem 542

For Beams (B - 3)

542-beam-b3.jpg$M_{max} = \frac{1}{8}(20)(62)$
$M_{max} = 90 \, \text{kN}\cdot\text{m}$
 
$S_{required} = \dfrac{M_{max}}{f_b} = \dfrac{90(1000^2)}{120}$
$S_{required} = 750 \times 10^3 \, \text{mm}^3$
 

From Appendix B, Table B-2 Properties of Wide Flange Sections (W Shapes): SI Units, of text book:

For Beams (B - 2) | Solution to Problem 542

For Beams (B - 2)

542-beam-b2.jpg$\Sigma M_{R2} = 0$
$6R_1 = 20(4) + 10(2)(5) + 15(4)(2)$
$R_1 = 50 \, \text{kN}$
 
$\Sigma M_{R1} = 0$
$6R_2 = 20(2) + 10(2)(1) + 15(4)(4)$
$R_2 = 50 \, \text{kN}$
 

For Girder (G - 1) | Solution to Problem 542

For Girder (G - 1)
542-girder-g1.jpg$S_{live-load} = \dfrac{M}{f_b} = \dfrac{40(1000^2)}{120}$
$S_{live-load} = 333.33 \times 10^3 \, \text{mm}^3$
 

From Appendix B, Table B-2 Properties of Wide-Flange Sections (W Shapes): SI Units, of text book:

Solution to Problem 542 | Floor Framing

Problem 542
Select the lightest W shape sections that can be used for the beams and girders in Illustrative Problem 537 of text book if the allowable flexural stress is 120 MPa. Neglect the weights of the members.
 

Solution to Problem 541 | Floor Framing

Problem 541
The 18-ft long floor beams in a building are simply supported at their ends and carry a floor load of 0.6 lb/in2. If the beams have W10 × 30 sections, determine the center-line spacing using an allowable flexural stress of 18 ksi.
 

Solution to Problem 540 | Floor Framing

Problem 540
Timbers 8 inches wide by 12 inches deep and 15 feet long, supported at top and bottom, back up a dam restraining water 9 feet deep. Water weighs 62.5 lb/ft3. (a) Compute the center-line spacing of the timbers to cause fb = 1000 psi. (b) Will this spacing be safe if the maximum fb, (fb)max = 1600 psi, and the water reaches its maximum depth of 15 ft?
 

Solution to Problem 539 | Floor Framing

Problem 539
Timbers 12 inches by 12 inches, spaced 3 feet apart on centers, are driven into the ground and act as cantilever beams to back-up the sheet piling of a coffer dam. What is the maximum safe height of water behind the dam if water weighs = 62.5 lb/ft3 and ( fb )max = 1200 psi?
 

Solution 539

Solution to Problem 538 | Floor Framing

Problem 538
Floor joists 50 mm wide by 200 mm high, simply supported on a 4-m span, carry a floor loaded at 5 kN/m2. Compute the center-line spacing between joists to develop a bending stress of 8 MPa. What safe floor load could be carried on a center-line spacing of 0.40 m?
 

Solution 538

 
 
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