# simple beam

## Solution to Problem 654 | Deflections in Simply Supported Beams

**Problem 654**

For the beam in Fig. P-654, find the value of EIδ at 2 ft from R_{2}. (Hint: Draw the reference tangent to the elastic curve at R_{2}.)

## Solution to Problem 653 | Deflections in Simply Supported Beams

**Problem 653**

Compute the midspan value of EIδ for the beam shown in Fig. P-653. (Hint: Draw the M diagram by parts, starting from midspan toward the ends. Also take advantage of symmetry to note that the tangent drawn to the elastic curve at midspan is horizontal.)

## Deflections in Simply Supported Beams | Area-Moment Method

The deflection δ at some point B of a simply supported beam can be obtained by the following steps:

## Solution to Problem 629 | Moment Diagrams by Parts

**Problem 629**

Solve Prob. 628 if the sense of **the couple is counterclockwise instead of clockwise** as shown in Fig. P-628.

## Solution to Problem 628 | Moment Diagrams by Parts

**Problem 628**

For the beam loaded with uniformly varying load and a couple as shown in Fig. P-628 compute the moment of area of the M diagrams between the reactions about both the left and the right reaction.

## Solution to Problem 627 | Moment Diagram by Parts

**Problem 627**

For the beam loaded as shown in Fig. P-627compute the moment of area of the M diagrams between the reactions about both the left and the right reaction. (Hint: Resolve the trapezoidal loading into a uniformly distributed load and a uniformly varying load.)

## Solution to Problem 624 | Moment Diagram by Parts

**Problem 624**

For the beam loaded as shown in Fig. P-624, compute the moment of area of the M diagrams between the reactions about both the left and the right reaction.

## Solution to Problem 620 | Double Integration Method

**Problem 620**

Find the midspan deflection δ for the beam shown in Fig. P-620, carrying two triangularly distributed loads. (*Hint:* For convenience, select the origin of the axes at the midspan position of the elastic curve.)