# Uniformly Distributed Load

## Solution to Problem 632 | Moment Diagrams by Parts

**Problem 632**

For the beam loaded as shown in Fig. P-632, compute the value of (Area_{AB}) barred(X)_{A}. From this result, is the tangent drawn to the elastic curve at B directed up or down to the right? (Hint: Refer to the deviation equations and rules of sign.)

## Solution to Problem 631 | Moment Diagrams by Parts

**Problem 631**

Determine the value of the couple M for the beam loaded as shown in Fig. P-631 so that the moment of area about A of the M diagram between A and B will be zero. What is the physical significance of this result?

## Solution to Problem 627 | Moment Diagram by Parts

**Problem 627**

For the beam loaded as shown in Fig. P-627compute the moment of area of the M diagrams between the reactions about both the left and the right reaction. (Hint: Resolve the trapezoidal loading into a uniformly distributed load and a uniformly varying load.)

## Moment Diagram by Parts

The moment-area method of finding the deflection of a beam will demand the accurate computation of the area of a moment diagram, as well as the moment of such area about any axis. To pave its way, this section will deal on how to draw moment diagram by parts and to calculate the moment of such diagrams about a specified axis.

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## Solution to Problem 615 | Double Integration Method

**Problem 615**

Compute the value of EI y at the right end of the overhanging beam shown in Fig. P-615.

## Solution to Problem 613 | Double Integration Method

**Problem 613**

If E = 29 × 10^{6} psi, what value of I is required to limit the midspan deflection to 1/360 of the span for the beam in Fig. P-613?

## Solution to Problem 612 | Double Integration Method

**Problem 612**

Compute the midspan value of EI δ for the beam loaded as shown in Fig. P-612.