# Vertical Curve

## Problem 02 - Symmetrical Parabolic Curve

- Read more about Problem 02 - Symmetrical Parabolic Curve
- Log in or register to post comments

## Problem 01 - Symmetrical Parabolic Curve

**Problem**

A grade of -4.2% grade intersects a grade of +3.0% at Station 11 + 488.00 of elevations 20.80 meters. These two center gradelines are to be connected by a 260 meter vertical parabolic curve.

- At what station is the cross-drainage pipes be situated?
- If the overall outside dimensions of the reinforced concrete pipe to be installed is 95 cm, and the top of the culvert is 30 cm below the subgrade, what will be the invert elevation at the center?

- Read more about Problem 01 - Symmetrical Parabolic Curve
- Log in or register to post comments

## Parabolic Curve

**Vertical Parabolic Curve**

Vertical curves are used to provide gradual change between two adjacent vertical grade lines. The curve used to connect the two adjacent grades is parabola. Parabola offers smooth transition because its second derivative is constant. For a downward parabola with vertex at the origin, the standard equation is

$x^2 = -4ay$ or $y = -\dfrac{x^2}{4a}$.

- Read more about Parabolic Curve
- Log in or register to post comments