Submitted by Engr Jaydee on June 2, 2021 - 4:05pm
In square $ABCD$, $E$ is the midpoint of side $\overline{AB}$ and $F$ is a point of side $\overline{AD}$ such that $F$ is twice as near from $D$ as from $A$. $G$ is the intersection of the line segments $\overline{DE}$ and $\overline{CF}$. If $AB = 1\text{ cm}$, find the area of $\triangle CDG$.
There are several ways to solve this problem, please show your solutions.
Submitted by Jhun Vert on August 13, 2019 - 8:15am
From the figures shown below. Squares EGHI and KHJB are fixed. Show that the area of triangle ABH is constant regardless of the dimensions of square ADEF.
Figure 1
Figure 2