among 10000 random digits, find the probabilty that the 3 appers at most 950 times. please help, thank you.
By binomial distribution, the probability is
$1 - \displaystyle{\sum_{n=951}^{1000} \left(\dfrac{1}{10}\right)^n \left(\dfrac{9}{10} \right)^{1000-n}}$
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By binomial distribution, the probability is
$1 - \displaystyle{\sum_{n=951}^{1000} \left(\dfrac{1}{10}\right)^n \left(\dfrac{9}{10} \right)^{1000-n}}$
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