What number *x* > *x ^{n}*?

Where

*n*= positive integer greater than 1.

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Hi sir I guess there is no possible answer or cant solved this.

Supposed that n is greater than 1 let say 2, then assumed that X = 1 so 1=1^2 this could not be X>X^2.

If X=2 ; then 2 is not greater than 2^2

My answer is no possible answer..cant solve

Even if I apply log cant solve. I guess no sufficient number of X is greater than X^n when n is a positive integer greater than 1.

Please correct me if I am wrong. Thank you your website is a great help for my self review in our upcoming SPLBE for Engineering board exam here in the middle east.

This can be possible for x > 0 but x < 1. Example: 1/2 > 1/4.

Thank you for the feed back, we are happy it helps you in certain way. We are starting to upload past board for CE. Our sole purpose is to help graduates of CE in the middle east but no PRC license yet. We are at a very early stage of doing it; less than a month. The contents of past CE board is very few but it can give you a glimpse of what type of problems are coming.

Thank you sir.

0 < x < 1

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