Problem 05 - Variation of Pressure

Problem
At what depth in a stand pipe containing water is the pressure 200 kPa?
 

Problem 04 - Variation of Pressure

Problem
What height of mercury column will cause a pressure of 680 kPa? What is the equivalent height of water column?
 

Problem 03 - Variation of Pressure

Problem
Take sea water to be 3% heavier than fresh water and assume it is incompressible. What is the pressure, in metric ton per square meter, at 3.22 km below the surface of the ocean if fresh water weighs 9.79 kN/m3?
 

Problem 02 - Variation of Pressure

Problem
Determine the pressure on the face of a dam at a point 12 m below the water surface, in (a) kilo Pascal gauge; (b) kilogram per square meter gauge; (c) kilo Pascal absolute; (d) pounds per square foot gauge; (e) pounds per square inch gauge; and (e) pounds per square inch absolute.
 

Problem 01 - Variation of Pressure

Problem
Determine the pressure in a vessel of mercury, specific gravity 13.6, at a point 20 cm below the surface. Express the answer in N/m2.
 

Variation of Pressure with Depth in a Fluid

Consider two points 1 and 2 lie in the ends of fluid prism having a cross-sectional area dA and length L. The difference in elevation between these two points is h as shown in Figure 02 below. The fluid is at rest and its surface is free. The prism is therefore in equilibrium and all forces acting on it sums up to zero.
 

000-variations-in-pressure.gif

 

Note: FFS stands for Free Fluid Surface which refers to fluid surface subject to zero gauge pressure.
 

Principles of Hydrostatic Pressures

Unit Pressure
Unit pressure or simply called pressure is the amount of force exerted by a fluid distributed uniformly over a unit area.
 

$p = \dfrac{Force, \, F}{Area, \, A}$

 

If the unit pressure is not uniform over the unit area, it can be expressed as the sum of differential pressure.
 

$\displaystyle p = \int \dfrac{dF}{dA}$

 

001-blaise-pascal.jpg
Blaise Pascal (1623 – 1662)

 

Since fluid at rest cannot resist shearing stress, pressure is always at right angle to the area where it is acting. It is also worthy to note that the total hydrostatic force F = pA, which can be found by cross multiplication.
 

Problem 01 | Stress in Helical Spring

Situation
The helical spring shown is axially loaded with a compression force P equal to 5 kN. The mean diameter of the spring is 100 mm and the wire used is 10 mm as indicated in the figure.

  1. What is the shear stress at A?
  2. What is the shear stress at B?
  3. On diameter AB, locate the point of zero stress measured from C.

 

001-spring-torque-plus-shear.png

 

Problem 908 | Combined Axial and Bending

 Problem 908
A punch press has the cast steel frame shown in Figure P-908. Determine the greatest force P that can be exerted at the jaws of the punch without exceeding a stress of 18 ksi at section A-B. The properties of the area are as shown and 1-1 is the centroidal axis.
 

908-punch-press.gif

 

Problem 907 | Combined Axial and Bending

Problem 907
Determine the largest load P that can be supported by the circular steel bracket shown in Figure P-907 if the normal stress on section A-B is limited to 80 MPa.
 

907-circular-bracket.gif

 

Pages

Subscribe to MATHalino RSS