Problem 04 - Variation of Pressure

$h_{mercury} = \dfrac{p}{s_{mercury} \, \gamma_{water}}$

$h_{mercury} = \dfrac{680}{13.6(9.81)}$

$h_{mercury} = 5.10 \, \text{m}$           answer
 

$h_{water} = s_{mercury} \, h_{mercury}$

$h_{water} = 13.6(5.10)$

$h_{water} = 69.32 \, \text{m}$           answer