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The formula for the radius of the circle circumscribed about a triangle (circumcircle) is given by

$R = \dfrac{abc}{4A_t}$

where A_{t} is the area of the inscribed triangle.

**Derivation:**

If you have some questions about the angle θ shown in the figure above, see the relationship between inscribed and central angles.

From triangle BDO

$\sin \theta = \dfrac{a/2}{R}$

$\sin \theta = \dfrac{a}{2R}$

A_{t} = area of triangle ABC

$A_t = \frac{1}{2}bc \sin \theta$

$A_t = \frac{1}{2}bc \left( \dfrac{a}{2R} \right)$

$A_t = \dfrac{abc}{4R}$

$R = \dfrac{abc}{4A_t}$