03 Area enclosed by pairs of overlapping quarter circles

$A_{CED} = 8.68 \, \text{ cm}^2$       → See how it was found
 

Area of CEB
$A_{CEB} = A_{square} - A_{OABCF} - 4A_{CED}$

$A_{CEB} = 20^2 - \frac{1}{4} \pi (20^2) - 4(8.68)$

$A_{CEB} = 51.12 \, \text{ cm}^2$
 

Required Area
$A_{required} = 4A_{CEB} = 4(51.12)$

$A_{required} = 204.48 \, \text{ cm}^2$           answer