Solved Problem 03 | Cube

Unit weight of ice
$\gamma_{ice} = 92\% \, \gamma_{water}$

$\gamma_{ice} = 0.92(62.5)$

$\gamma_{ice} = 57.5 \, \text{ lb/ft}^3$
 

Volume of ice block
$V_{ice} = (24/12)^3$

$V_{ice} = 8 \, \text{ ft}^3$
 

Weight of 8 ft³ ice block
$W_{ice} = \gamma_{ice}V_{ice}$

$W_{ice} = 57.5(8)$

$W_{ice} = 460 \, \text{ lb}$           answer

$W_{ice} = 0.92(62.5)(24/12)^3$

$W_{ice} = 460 \, \text{ lb}$       okay!