$\theta = \dfrac{TL}{JG}$
Rotation of D relative to A:
$\theta_{D/A} = \dfrac{1}{JG} \Sigma TL$
$\theta_{D/A} = \dfrac{1}{\frac{1}{32}\pi (50^4)(28\,000)} \, [ \, 800(2) - 300(3) + 600(2) \, ] \, (1000^2)$
$\theta_{D/A} = 0.1106 \, \text{rad}$
$\theta_{D/A} = 6.34^\circ$ answer